Project Euler 001.c


  1 |  /*///-----------------------------------------------------------------
  2 |   *  Project Euler Problem 001
  3 |   *  File Name   : pe-001.c
  4 |   *  Author      : Yen-Chin,Lee
  5 |   *  Email       : coldnew.tw@gmail.com
  6 |   *  Create Date : 2009/03/12 18:22:32
  7 |   *  Description :
  8 |   *
  9 |   *  Problem     :
 10 |   *
 11 |   *  If we list all the natural numbers below 10 that are multiples
 12 |   *  of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
 13 |   *
 14 |   *  Find the sum of all the multiples of 3 or 5 below 1000.
 15 |   *
 16 |  /*///---------------------------- Copyright (C) ,2009 coldnew --------
 17 |  
 18 |  #include <stdio.h>
 19 |  #include <stdlib.h>
 20 |  
 21 |  int main( int argc, char **argv)
 22 |  {
 23 |          int i = 0;
 24 |          int sum = 0;
 25 |          for ( i = 0; i < 1000; i++) {
 26 |                  if (0 == i % 3 || 0 == i % 5 ) {
 27 |                          sum += i;
 28 |                  }
 29 |                          
 30 |          }
 31 |          printf("%d",sum);
 32 |       return 0;
 33 |  }
 34 |